Integral of 3dx/sqrt2x-5 dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant is the constant times the variable of integration:
∫(−5)dx=−5x
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The integral of a constant times a function is the constant times the integral of the function:
∫2x3dx=3∫2x1dx
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Let u=2x.
Then let du=2x2dx and substitute du:
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The integral of a constant is the constant times the variable of integration:
∫1du=u
Now substitute u back in:
So, the result is: 32x
The result is: 32x−5x
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Add the constant of integration:
32x−5x+constant
The answer is:
32x−5x+constant
The answer (Indefinite)
[src]
/
|
| / 3 \ ___ ___
| |------- - 5| dx = C - 5*x + 3*\/ 2 *\/ x
| | _____ |
| \\/ 2*x /
|
/
∫(−5+2x3)dx=C+32x−5x
The graph
−5+32
=
−5+32
Use the examples entering the upper and lower limits of integration.