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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of 5
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Integral of x*exp(x)
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Integral of -e^-x
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Integral of e^x/x
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Identical expressions
- (2x^ seven -x^ six -2x^ four +4x^ three -4x²- three)/(x^ three - one)
- (2x to the power of 7 minus x to the power of 6 minus 2x to the power of 4 plus 4x cubed minus 4x² minus 3) divide by (x cubed minus 1)
- (2x to the power of seven minus x to the power of six minus 2x to the power of four plus 4x to the power of three minus 4x² minus three) divide by (x to the power of three minus one)
- (2x7-x6-2x4+4x3-4x²-3)/(x3-1)
- 2x7-x6-2x4+4x3-4x²-3/x3-1
- (2x⁷-x⁶-2x⁴+4x³-4x²-3)/(x³-1)
- (2x to the power of 7-x to the power of 6-2x to the power of 4+4x to the power of 3-4x²-3)/(x to the power of 3-1)
- 2x^7-x^6-2x^4+4x^3-4x²-3/x^3-1
- (2x^7-x^6-2x^4+4x^3-4x²-3) divide by (x^3-1)
- (2x^7-x^6-2x^4+4x^3-4x²-3)/(x^3-1)dx
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Similar expressions
- (2x^7-x^6-2x^4+4x^3-4x²+3)/(x^3-1)
- (2x^7-x^6+2x^4+4x^3-4x²-3)/(x^3-1)
- (2x^7+x^6-2x^4+4x^3-4x²-3)/(x^3-1)
- (2x^7-x^6-2x^4+4x^3+4x²-3)/(x^3-1)
- (2x^7-x^6-2x^4+4x^3-4x²-3)/(x^3+1)
- (2x^7-x^6-2x^4-4x^3-4x²-3)/(x^3-1)
Integral of (2x^7-x^6-2x^4+4x^3-4x²-3)/(x^3-1) dx
The solution
You have entered
[src]
0 / | | 7 6 4 3 2 | 2*x - x - 2*x + 4*x - 4*x - 3 | ---------------------------------- dx | 3 | x - 1 | / 0
$$\int\limits_{0}^{0} \frac{2 x^{7} - x^{6} - 2 x^{4} + 4 x^{3} - 4 x^{2} - 3}{x^{3} - 1}\, dx$$
Integral((2*x^7 - x^6 - 2*x^4 + 4*x^3 - 4*x^2 - 1*3)/(x^3 - 1*1), (x, 0, 0))
The answer (Indefinite)
[src]
/ | | 7 6 4 3 2 / 2\ 4 5 | 2*x - x - 2*x + 4*x - 4*x - 3 4*log(-1 + x) 4*log\1 + x + x / x 2*x | ---------------------------------- dx = C + 3*x - ------------- - ----------------- - -- + ---- | 3 3 3 4 5 | x - 1 | /
$$\int \frac{2 x^{7} - x^{6} - 2 x^{4} + 4 x^{3} - 4 x^{2} - 3}{x^{3} - 1}\, dx = C + \frac{2 x^{5}}{5} - \frac{x^{4}}{4} + 3 x - \frac{4 \log{\left(x - 1 \right)}}{3} - \frac{4 \log{\left(x^{2} + x + 1 \right)}}{3}$$
The graph
The graph
Use the examples entering the upper and lower limits of integration.