Integral of 2sinx-3cosx dx

1. Integrate term-by-term:

   1. The integral of a constant times a function is the constant times the integral of the function:

      $$\int 2 \sin{\left(x \right)}\, dx = 2 \int \sin{\left(x \right)}\, dx$$

      1. The integral of sine is negative cosine:

         $$\int \sin{\left(x \right)}\, dx = - \cos{\left(x \right)}$$

      So, the result is: $- 2 \cos{\left(x \right)}$

   1. The integral of a constant times a function is the constant times the integral of the function:

      $$\int \left(- 3 \cos{\left(x \right)}\right)\, dx = - 3 \int \cos{\left(x \right)}\, dx$$

      1. The integral of cosine is sine:

         $$\int \cos{\left(x \right)}\, dx = \sin{\left(x \right)}$$

      So, the result is: $- 3 \sin{\left(x \right)}$

   The result is: $- 3 \sin{\left(x \right)} - 2 \cos{\left(x \right)}$

2. Add the constant of integration:

   $$- 3 \sin{\left(x \right)} - 2 \cos{\left(x \right)}+ \mathrm{constant}$$

The answer is:

$$- 3 \sin{\left(x \right)} - 2 \cos{\left(x \right)}+ \mathrm{constant}$$