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Solving integrals/ 2sincosxdx

Integral of 2sincosxdx dx

Limits of integration:

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The solution

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 |  2*sin(cos(x)) dx
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∫012sin⁡(cos⁡(x)) dx\int\limits_{0}^{1} 2 \sin{\left(\cos{\left(x \right)} \right)}\, dx 
Integral(2*sin(cos(x)), (x, 0, 1))
Detail solution

  1. The integral of a constant times a function is the constant times the integral of the function:

    ∫2sin⁡(cos⁡(x)) dx=2∫sin⁡(cos⁡(x)) dx\int 2 \sin{\left(\cos{\left(x \right)} \right)}\, dx = 2 \int \sin{\left(\cos{\left(x \right)} \right)}\, dx

    1. Don't know the steps in finding this integral.

      But the integral is

      ∫sin⁡(cos⁡(x)) dx\int \sin{\left(\cos{\left(x \right)} \right)}\, dx

    So, the result is: 2∫sin⁡(cos⁡(x)) dx2 \int \sin{\left(\cos{\left(x \right)} \right)}\, dx

  2. Add the constant of integration:

    2∫sin⁡(cos⁡(x)) dx+constant2 \int \sin{\left(\cos{\left(x \right)} \right)}\, dx+ \mathrm{constant}

The answer is:

2∫sin⁡(cos⁡(x)) dx+constant2 \int \sin{\left(\cos{\left(x \right)} \right)}\, dx+ \mathrm{constant}

The answer (Indefinite) [src] 
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 | 2*sin(cos(x)) dx = C + 2* | sin(cos(x)) dx
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∫2sin⁡(cos⁡(x)) dx=C+2∫sin⁡(cos⁡(x)) dx\int 2 \sin{\left(\cos{\left(x \right)} \right)}\, dx = C + 2 \int \sin{\left(\cos{\left(x \right)} \right)}\, dx
Simplify
The answer [src] 
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2* |  sin(cos(x)) dx
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2∫01sin⁡(cos⁡(x)) dx2 \int\limits_{0}^{1} \sin{\left(\cos{\left(x \right)} \right)}\, dx 
=
= 
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2* |  sin(cos(x)) dx
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2∫01sin⁡(cos⁡(x)) dx2 \int\limits_{0}^{1} \sin{\left(\cos{\left(x \right)} \right)}\, dx 
2*Integral(sin(cos(x)), (x, 0, 1))
Numerical answer [src] 
1.47728599607378
1.47728599607378

    Use the examples entering the upper and lower limits of integration.

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