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  • Identical expressions

  • 16cost^ two *sin(two t)*sqrt(16sint^ two +4cos(2t)^2)
  • 16 co sinus of e of t squared multiply by sinus of (2t) multiply by square root of (16 sinus of t squared plus 4 co sinus of e of (2t) squared )
  • 16 co sinus of e of t to the power of two multiply by sinus of (two t) multiply by square root of (16 sinus of t to the power of two plus 4 co sinus of e of (2t) squared )
  • 16cost^2*sin(2t)*√(16sint^2+4cos(2t)^2)
  • 16cost2*sin(2t)*sqrt(16sint2+4cos(2t)2)
  • 16cost2*sin2t*sqrt16sint2+4cos2t2
  • 16cost²*sin(2t)*sqrt(16sint²+4cos(2t)²)
  • 16cost to the power of 2*sin(2t)*sqrt(16sint to the power of 2+4cos(2t) to the power of 2)
  • 16cost^2sin(2t)sqrt(16sint^2+4cos(2t)^2)
  • 16cost2sin(2t)sqrt(16sint2+4cos(2t)2)
  • 16cost2sin2tsqrt16sint2+4cos2t2
  • 16cost^2sin2tsqrt16sint^2+4cos2t^2

  • Similar expressions

  • 16cost^2*sin(2t)*sqrt(16sint^2-4cos(2t)^2)
Solving integrals/ 16cost^2*sin(2t)*sqrt(16sint^2+4cos(2t)^2)

Integral of 16cost^2*sin(2t)*sqrt(16sint^2+4cos(2t)^2) dx

Limits of integration:

from to
v

The graph:

from to

Piecewise:

The solution

You have entered [src] 
  1                                                     
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 |        2               /       2           2         
 |  16*cos (t)*sin(2*t)*\/  16*sin (t) + 4*cos (2*t)  dt
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0
$$\int\limits_{0}^{1} \sin{\left(2 t \right)} 16 \cos^{2}{\left(t \right)} \sqrt{16 \sin^{2}{\left(t \right)} + 4 \cos^{2}{\left(2 t \right)}}\, dt$$ 
Integral(((16*cos(t)^2)*sin(2*t))*sqrt(16*sin(t)^2 + 4*cos(2*t)^2), (t, 0, 1))
Numerical answer [src] 
17.5915782514811
17.5915782514811

    Use the examples entering the upper and lower limits of integration.

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