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Integral of (12x¾-9x^5/3)dx dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫43⋅12xdx=43∫12xdx
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The integral of a constant times a function is the constant times the integral of the function:
∫12xdx=12∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: 6x2
So, the result is: 29x2
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The integral of a constant times a function is the constant times the integral of the function:
∫(−39x5)dx=−3∫9x5dx
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The integral of a constant times a function is the constant times the integral of the function:
∫9x5dx=9∫x5dx
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The integral of xn is n+1xn+1 when n=−1:
∫x5dx=6x6
So, the result is: 23x6
So, the result is: −2x6
The result is: −2x6+29x2
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Now simplify:
2x2(9−x4)
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Add the constant of integration:
2x2(9−x4)+constant
The answer is:
2x2(9−x4)+constant
The answer (Indefinite)
[src]
/
|
| / 5\ 6 2
| |12*x*3 9*x | x 9*x
| |------ - ----| dx = C - -- + ----
| \ 4 3 / 2 2
|
/
∫(43⋅12x−39x5)dx=C−2x6+29x2
The graph
Use the examples entering the upper and lower limits of integration.