Given the inequality:
$$\frac{9 x}{10} < \frac{27}{5}$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{9 x}{10} = \frac{27}{5}$$
Solve:
Given the linear equation:
(9/10)*x = (27/5)
Expand brackets in the left part
9/10x = (27/5)
Expand brackets in the right part
9/10x = 27/5
Divide both parts of the equation by 9/10
x = 27/5 / (9/10)
$$x_{1} = 6$$
$$x_{1} = 6$$
This roots
$$x_{1} = 6$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + 6$$
=
$$\frac{59}{10}$$
substitute to the expression
$$\frac{9 x}{10} < \frac{27}{5}$$
$$\frac{9 \cdot 59}{10 \cdot 10} < \frac{27}{5}$$
531
--- < 27/5
100
the solution of our inequality is:
$$x < 6$$
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