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How to use it?
- Inequation:
- x^2*log512(x+5)>=log2(x^2+10x+25)
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cos(2x)<-0.5
- log⅓2*log5(x-2)>0
- x*(x-2)^2*(x-4)^855/(((1-x)*(x-3)^66*(x^2-(11/2)^2)))>=0
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Identical expressions
- x^ two *log five 1 two (x+5)>=log2(x^2+10x+ twenty-five)
- x squared multiply by logarithm of 512(x plus 5) greater than or equal to logarithm of 2(x squared plus 10x plus 25)
- x to the power of two multiply by logarithm of five 1 two (x plus 5) greater than or equal to logarithm of 2(x squared plus 10x plus twenty minus five)
- x2*log512(x+5)>=log2(x2+10x+25)
- x2*log512x+5>=log2x2+10x+25
- x²*log512(x+5)>=log2(x²+10x+25)
- x to the power of 2*log512(x+5)>=log2(x to the power of 2+10x+25)
- x^2log512(x+5)>=log2(x^2+10x+25)
- x2log512(x+5)>=log2(x2+10x+25)
- x2log512x+5>=log2x2+10x+25
- x^2log512x+5>=log2x^2+10x+25
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Similar expressions
- x^2*log512(x+5)>=log2(x^2-10x+25)
- x^2*log512(x+5)>=log2(x^2+10x-25)
- x^2*log512(x-5)>=log2(x^2+10x+25)
x^2*log512(x+5)>=log2(x^2+10x+25) inequation
The solution
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[src]
/ 2 \
2 log(x + 5) log\x + 10*x + 25/
x *---------- >= -------------------
log(512) log(2)
$$x^{2} \frac{\log{\left(x + 5 \right)}}{\log{\left(512 \right)}} \geq \frac{\log{\left(\left(x^{2} + 10 x\right) + 25 \right)}}{\log{\left(2 \right)}}$$
x^2*(log(x + 5)/log(512)) >= log(x^2 + 10*x + 25)/log(2)