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Other calculators
- Square Inequality Step-by-Step
- Inequality with the module Step by Step
- Logarithmic inequality online
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How to use it?
- Inequation:
- (3x+5)(1-x)(x+1)^2>=0
- (x+1)*log(x+4)<0
- 25^x+0,5+4•5^x-1>=0
- (2x-7)\(4-x)>=0
- Graphing y =:
- (x+2)^2
- Derivative of:
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(x+2)^2
- Canonical form:
- (x+2)^2
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Identical expressions
- (x+ two)^ two > four (x+ two)
- (x plus 2) squared greater than 4(x plus 2)
- (x plus two) to the power of two greater than four (x plus two)
- (x+2)2>4(x+2)
- x+22>4x+2
- (x+2)²>4(x+2)
- (x+2) to the power of 2>4(x+2)
- x+2^2>4x+2
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Similar expressions
- (x-4)*(x+2)*(2x-1)>=0
- (x-2)^2>4(x+2)
- sin(1/4x+2п/3)>=-√2/2
- (x^3+2*2^x+3)^3>(x^3+4^x+2^x)^3
- (x+2)^2>4(x-2)
- 2*(1/4)^x-5(1/4)^x+2>0
(x+2)^2>4(x+2) inequation
The solution
You have entered
[src]
2 (x + 2) > 4*(x + 2)
$$\left(x + 2\right)^{2} > 4 \left(x + 2\right)$$
(x + 2)^2 > 4*(x + 2)
Solving inequality on a graph
Rapid solution
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Or(And(-oo < x, x < -2), And(2 < x, x < oo))
$$\left(-\infty < x \wedge x < -2\right) \vee \left(2 < x \wedge x < \infty\right)$$
((-oo < x)∧(x < -2))∨((2 < x)∧(x < oo))
Rapid solution 2
[src]
(-oo, -2) U (2, oo)
$$x\ in\ \left(-\infty, -2\right) \cup \left(2, \infty\right)$$
x in Union(Interval.open(-oo, -2), Interval.open(2, oo))