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How to use it?
- Inequation:
- 2^(2*x)-7*2^x-1-1+5>0
- x+29<38
- sqrt(x)<=√2/2
- (-14)/(x^2+x-6)<=o
- Sum of series:
-
38
-
Identical expressions
- x+ twenty-nine < thirty-eight
- x plus 29 less than 38
- x plus twenty minus nine less than thirty minus eight
-
Similar expressions
- (4q-1)^2>(2q+3)(8q-1)
- x-29<38
- 3^(x+2)9^x+8<9^x+8
- (x+2)9-x^2>0
- (x-3)(8-x)<0
- -18*15^x-27^x-3^4*3^x+45^x+81*5^x+2*9*9^x<=0
- (3^8x-5*27^5x)/(9^(x^2+3.5))>=1/3
x+29<38 inequation
The solution
Detail solution
Given the inequality:
$$x + 29 < 38$$
To solve this inequality, we must first solve the corresponding equation:
$$x + 29 = 38$$
Solve:
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$x = 9$$
$$x_{1} = 9$$
$$x_{1} = 9$$
This roots
$$x_{1} = 9$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + 9$$
=
$$\frac{89}{10}$$
substitute to the expression
$$x + 29 < 38$$
$$\frac{89}{10} + 29 < 38$$
the solution of our inequality is:
$$x < 9$$
$$x + 29 < 38$$
To solve this inequality, we must first solve the corresponding equation:
$$x + 29 = 38$$
Solve:
Given the linear equation:
x+29 = 38
Move free summands (without x)
from left part to right part, we given:
$$x = 9$$
$$x_{1} = 9$$
$$x_{1} = 9$$
This roots
$$x_{1} = 9$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + 9$$
=
$$\frac{89}{10}$$
substitute to the expression
$$x + 29 < 38$$
$$\frac{89}{10} + 29 < 38$$
379 --- < 38 10
the solution of our inequality is:
$$x < 9$$
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