x+(8/5)>2 inequation

Given the inequality:
$$x + \frac{8}{5} > 2$$
To solve this inequality, we must first solve the corresponding equation:
$$x + \frac{8}{5} = 2$$
Solve:
Given the linear equation:

x+(8/5) = 2

Expand brackets in the left part

x+8/5 = 2

Move free summands (without x)
from left part to right part, we given:
$$x = \frac{2}{5}$$
$$x_{1} = \frac{2}{5}$$
$$x_{1} = \frac{2}{5}$$
This roots
$$x_{1} = \frac{2}{5}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + \frac{2}{5}$$
=
$$\frac{3}{10}$$
substitute to the expression
$$x + \frac{8}{5} > 2$$
$$\frac{3}{10} + \frac{8}{5} > 2$$

19    
-- > 2
10    

Then
$$x < \frac{2}{5}$$
no execute
the solution of our inequality is:
$$x > \frac{2}{5}$$

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