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Inequation:
6+3x≥4-x
log(x^2+2*x+2)+5<=-2*x-x2+4
(x-2)*(x+4)≦0
2(3-x)-3(2+x)<_x
Identical expressions
two (three -x)- three (two +x)<_x
2(3 minus x) minus 3(2 plus x) less than _x
two (three minus x) minus three (two plus x) less than _x
23-x-32+x<_x
Similar expressions
2(3+x)-3(2+x)<_x
2(3-x)+3(2+x)<_x
2(3-x)-3(2-x)<_x

Solving inequalities/ 2(3-x)-3(2+x)<_x

2(3-x)-3(2+x)<_x inequation

The solution

You have entered [src]

2*(3 - x) - 3*(2 + x) <= x

$$2 \left(3 - x\right) - 3 \left(x + 2\right) \leq x$$

2*(3 - x) - 3*(x + 2) <= x

Solving inequality on a graph

Rapid solution 2 [src]

[0, oo)

$$x\ in\ \left[0, \infty\right)$$

x in Interval(0, oo)

Rapid solution [src]

And(0 <= x, x < oo)

$$0 \leq x \wedge x < \infty$$

(0 <= x)∧(x < oo)