2*x+10≤0 inequation

Given the inequality:
$$2 x + 10 \leq 0$$
To solve this inequality, we must first solve the corresponding equation:
$$2 x + 10 = 0$$
Solve:
Given the linear equation:

2*x+10 = 0

Move free summands (without x)
from left part to right part, we given:
$$2 x = -10$$
Divide both parts of the equation by 2

x = -10 / (2)

$$x_{1} = -5$$
$$x_{1} = -5$$
This roots
$$x_{1} = -5$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} \leq x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$-5 + - \frac{1}{10}$$
=
$$- \frac{51}{10}$$
substitute to the expression
$$2 x + 10 \leq 0$$
$$\frac{\left(-51\right) 2}{10} + 10 \leq 0$$

-1/5 <= 0

the solution of our inequality is:
$$x \leq -5$$

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