2*sqrt(x+4)>0 inequation

Given the inequality:
$$2 \sqrt{x + 4} > 0$$
To solve this inequality, we must first solve the corresponding equation:
$$2 \sqrt{x + 4} = 0$$
Solve:
Given the equation
$$2 \sqrt{x + 4} = 0$$
so
$$x + 4 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$x = -4$$
We get the answer: x = -4
$$x_{1} = -4$$
$$x_{1} = -4$$
This roots
$$x_{1} = -4$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$-4 + - \frac{1}{10}$$
=
$$- \frac{41}{10}$$
substitute to the expression
$$2 \sqrt{x + 4} > 0$$
$$2 \sqrt{- \frac{41}{10} + 4} > 0$$

    ____    
I*\/ 10     
-------- > 0
   5        
    

Then
$$x < -4$$
no execute
the solution of our inequality is:
$$x > -4$$

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