2(4−3y)+4(10−y)≥60 inequation

Given the inequality:
$$2 \left(4 - 3 y\right) + 4 \left(10 - y\right) \geq 60$$
To solve this inequality, we must first solve the corresponding equation:
$$2 \left(4 - 3 y\right) + 4 \left(10 - y\right) = 60$$
Solve:
$$x_{1} = -1.2$$
$$x_{1} = -1.2$$
This roots
$$x_{1} = -1.2$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} \leq x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$-1.2 + - \frac{1}{10}$$
=
$$-1.3$$
substitute to the expression
$$2 \left(4 - 3 y\right) + 4 \left(10 - y\right) \geq 60$$
$$2 \left(4 - 3 y\right) + 4 \left(10 - y\right) \geq 60$$

48 - 10*y >= 60

Then
$$x \leq -1.2$$
no execute
the solution of our inequality is:
$$x \geq -1.2$$

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