Mister Exam

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How to use it?
Inequation:
2x-1:5-x>_0
6+12x≤0
(1/4)*(2^(x^2+x))^(1/6)>=1
2x^2-5x^2+2>=0
Integral of d{x}:
1/(2x+3)
Graphing y =:
1/(2x+3)
Identical expressions
two /(x- one)+ one /(x+ two)> one /(2x+ three)
2 divide by (x minus 1) plus 1 divide by (x plus 2) greater than 1 divide by (2x plus 3)
two divide by (x minus one) plus one divide by (x plus two) greater than one divide by (2x plus three)
2/x-1+1/x+2>1/2x+3
2 divide by (x-1)+1 divide by (x+2)>1 divide by (2x+3)
Similar expressions
1/2x+3<_2x-1
2/(x-1)+1/(x-2)>1/(2x+3)
1/2*x+3<2*x-1
2/(x+1)+1/(x+2)>1/(2x+3)
-21/5x+1,4>-41/2x+3,6
2/(x-1)-1/(x+2)>1/(2x+3)
(1/2)x+35->8
2/(x-1)+1/(x+2)>1/(2x-3)

2/(x-1)+1/(x+2)>1/(2x+3) inequation

You have entered [src]

  2       1        1   
----- + ----- > -------
x - 1   x + 2   2*x + 3

$$\frac{1}{x + 2} + \frac{2}{x - 1} > \frac{1}{2 x + 3}$$

1/(x + 2) + 2/(x - 1) > 1/(2*x + 3)

Solving inequality on a graph

Rapid solution [src]

Or(And(-2 < x, x < -3/2), And(1 < x, x < oo))

$$\left(-2 < x \wedge x < - \frac{3}{2}\right) \vee \left(1 < x \wedge x < \infty\right)$$

((-2 < x)∧(x < -3/2))∨((1 < x)∧(x < oo))

Rapid solution 2 [src]

(-2, -3/2) U (1, oo)

$$x\ in\ \left(-2, - \frac{3}{2}\right) \cup \left(1, \infty\right)$$

x in Union(Interval.open(-2, -3/2), Interval.open(1, oo))