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How to use it?
- Inequation:
- 3(2x-4)<=-5(2-3x)
- log2((x-1)(x^2+3))<=log2(4*x-x^2-3)+log2(5-x)
- ln(x+4)+log0.3(3x+13)<3
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(x−5)(x−2)(x+1)≥0
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Identical expressions
- three (two x- four)<=- five (2-3x)
- 3(2x minus 4) less than or equal to minus 5(2 minus 3x)
- three (two x minus four) less than or equal to minus five (2 minus 3x)
- 32x-4<=-52-3x
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Similar expressions
- log(1/3)*(2*x-4)<log(1/3)*(x+3)
- 3(2x-4)<=-5(2+3x)
- (2x^5+15x^4+36x^3+27x^2-32x-48)/(x^2+3x)>=0
- (2-sqrt(3))^(2x)-4*(1/(2+sqrt(3))^x)+1<=0
- x^2-3*2^x-40>0
- 3(2x-4)<=+5(2-3x)
- 3(2x+4)<=-5(2-3x)
3(2x-4)<=-5(2-3x) inequation
The solution
You have entered
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3*(2*x - 4) <= -5*(2 - 3*x)
$$3 \left(2 x - 4\right) \leq - 5 \left(2 - 3 x\right)$$
3*(2*x - 4) <= -5*(2 - 3*x)
Solving inequality on a graph
Rapid solution
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And(-2/9 <= x, x < oo)
$$- \frac{2}{9} \leq x \wedge x < \infty$$
(-2/9 <= x)∧(x < oo)
Rapid solution 2
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[-2/9, oo)
$$x\ in\ \left[- \frac{2}{9}, \infty\right)$$
x in Interval(-2/9, oo)