Mister Exam

Lang:

How to use it?
Inequation:
(2/7)^3(x-1/3)<(4/49)^(x)^2
(x^2+x-20)/(x^2-6*x+y)>0
log(x+7)/log3+1/6*log(x+1)^6/log3=>2
(1+x)/(x-7)>=0
Identical expressions
three ^(x^ two)+ three hundred and twenty-four > thirteen ^(one -(x^ two))* thirty-nine ^(x^ two)
3 to the power of (x squared ) plus 324 greater than 13 to the power of (1 minus (x squared )) multiply by 39 to the power of (x squared )
three to the power of (x to the power of two) plus three hundred and twenty minus four greater than thirteen to the power of (one minus (x to the power of two)) multiply by thirty minus nine to the power of (x to the power of two)
3(x2)+324>13(1-(x2))*39(x2)
3x2+324>131-x2*39x2
3^(x²)+324>13^(1-(x²))*39^(x²)
3 to the power of (x to the power of 2)+324>13 to the power of (1-(x to the power of 2))*39 to the power of (x to the power of 2)
3^(x^2)+324>13^(1-(x^2))39^(x^2)
3(x2)+324>13(1-(x2))39(x2)
3x2+324>131-x239x2
3^x^2+324>13^1-x^239^x^2
Similar expressions
3^(x^2)+324>13^(1+(x^2))*39^(x^2)
3^(x^2)-324>13^(1-(x^2))*39^(x^2)

3^(x^2)+324>13^(1-(x^2))*39^(x^2) inequation

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 / 2\                2   / 2\
 \x /           1 - x    \x /
3     + 324 > 13      *39

$$3^{x^{2}} + 324 > 13^{1 - x^{2}} \cdot 39^{x^{2}}$$

3^(x^2) + 324 > 13^(1 - x^2)*39^(x^2)