sqrt(6-x)<sqrt(x^3-7*x^2+14*x+6)/(sqrt(x+1)) inequation

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Inequation:
log1/2*log5(x-2)>0
sqrt(6-x)<sqrt(x^3-7*x^2+14*x+6)/(sqrt(x+1))
(x+6*sqrt(x)+28)*1/120<(2-sqrt(x))*1/(x-6*sqrt(x)+8)
2/log(2)^(2x-2)+3/log2^(4x-4)<8/log3^27+log2^(x-1)
Graphing y =:
sqrt(6-x)
Identical expressions
sqrt(six -x)<sqrt(x^ three - seven *x^ two + fourteen *x+ six)/(sqrt(x+ one))
square root of (6 minus x) less than square root of (x cubed minus 7 multiply by x squared plus 14 multiply by x plus 6) divide by ( square root of (x plus 1))
square root of (six minus x) less than square root of (x to the power of three minus seven multiply by x to the power of two plus fourteen multiply by x plus six) divide by ( square root of (x plus one))
√(6-x)<√(x^3-7*x^2+14*x+6)/(√(x+1))
sqrt(6-x)<sqrt(x3-7*x2+14*x+6)/(sqrt(x+1))
sqrt6-x<sqrtx3-7*x2+14*x+6/sqrtx+1
sqrt(6-x)<sqrt(x³-7*x²+14*x+6)/(sqrt(x+1))
sqrt(6-x)<sqrt(x to the power of 3-7*x to the power of 2+14*x+6)/(sqrt(x+1))
sqrt(6-x)<sqrt(x^3-7x^2+14x+6)/(sqrt(x+1))
sqrt(6-x)<sqrt(x3-7x2+14x+6)/(sqrt(x+1))
sqrt6-x<sqrtx3-7x2+14x+6/sqrtx+1
sqrt6-x<sqrtx^3-7x^2+14x+6/sqrtx+1
sqrt(6-x)<sqrt(x^3-7*x^2+14*x+6) divide by (sqrt(x+1))
Similar expressions
sqrt(6-x)<sqrt(x^3-7*x^2-14*x+6)/(sqrt(x+1))
sqrt(6-x)<sqrt(x^3-7*x^2+14*x+6)/(sqrt(x-1))
sqrt(6+x)<sqrt(x^3-7*x^2+14*x+6)/(sqrt(x+1))
sqrt(6-x)<sqrt(x^3+7*x^2+14*x+6)/(sqrt(x+1))
sqrt3x+10>sqrt6-x
sqrt(5*x-x^2+6)<sqrt(6)-x
sqrt(6-x)<sqrt(x^3-7*x^2+14*x-6)/(sqrt(x+1))

Solving inequalities/ sqrt(6-x)

sqrt(6-x)

The solution

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               ______________________
              /  3      2            
  _______   \/  x  - 7*x  + 14*x + 6 
\/ 6 - x  < -------------------------
                      _______        
                    \/ x + 1

$$\sqrt{6 - x} < \frac{\sqrt{\left(14 x + \left(x^{3} - 7 x^{2}\right)\right) + 6}}{\sqrt{x + 1}}$$

sqrt(6 - x) < sqrt(14*x + x^3 - 7*x^2 + 6)/sqrt(x + 1)

Solving inequality on a graph

Rapid solution [src]

Or(And(x <= 6, 3 < x), And(0 < x, x < 3))

$$\left(x \leq 6 \wedge 3 < x\right) \vee \left(0 < x \wedge x < 3\right)$$

((x <= 6)∧(3 < x))∨((0 < x)∧(x < 3))

Rapid solution 2 [src]

(0, 3) U (3, 6]

$$x\ in\ \left(0, 3\right) \cup \left(3, 6\right]$$

x in Union(Interval.open(0, 3), Interval.Lopen(3, 6))

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