Mister Exam

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Inequation:
(x^3-3*x^2+3*x-3)/((x/x^3))<=x/1+1/(x-2)+1/x
x^2*log(512,4-x)>=log(2,x^2-8*x+16)
4x^2>=36
4^x-32^x+2≤6
Identical expressions
(sqrt(eleven -2x)/(5x- eleven))<((six -x)/(5x- eleven))
( square root of (11 minus 2x) divide by (5x minus 11)) less than ((6 minus x) divide by (5x minus 11))
( square root of (eleven minus 2x) divide by (5x minus eleven)) less than ((six minus x) divide by (5x minus eleven))
(√(11-2x)/(5x-11))<((6-x)/(5x-11))
sqrt11-2x/5x-11<6-x/5x-11
(sqrt(11-2x) divide by (5x-11))<((6-x) divide by (5x-11))
Similar expressions
(sqrt(11-2x)/(5x-11))<((6-x)/(5x+11))
(sqrt(11+2x)/(5x-11))<((6-x)/(5x-11))
(sqrt(11-2x)/(5x-11))<((6+x)/(5x-11))
(sqrt(11-2x)/(5x+11))<((6-x)/(5x-11))

(sqrt(11-2x)/(5x-11))<((6-x)/(5x-11)) inequation

You have entered [src]

  __________           
\/ 11 - 2*x     6 - x  
------------ < --------
  5*x - 11     5*x - 11

$$\frac{\sqrt{11 - 2 x}}{5 x - 11} < \frac{6 - x}{5 x - 11}$$

sqrt(11 - 2*x)/(5*x - 11) < (6 - x)/(5*x - 11)

Solving inequality on a graph

Rapid solution 2 [src]

(11/5, 5) U (5, 11/2]

$$x\ in\ \left(\frac{11}{5}, 5\right) \cup \left(5, \frac{11}{2}\right]$$

x in Union(Interval.open(11/5, 5), Interval.Lopen(5, 11/2))

Rapid solution [src]

Or(And(x <= 11/2, 5 < x), And(11/5 < x, x < 5))

$$\left(x \leq \frac{11}{2} \wedge 5 < x\right) \vee \left(\frac{11}{5} < x \wedge x < 5\right)$$

((x <= 11/2)∧(5 < x))∨((11/5 < x)∧(x < 5))