Given the inequality:
$$\frac{\sin{\left(x \right)}}{2 x - 1} < 1$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{\sin{\left(x \right)}}{2 x - 1} = 1$$
Solve:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
x0 = 0
$$\frac{\sin{\left(0 \right)}}{-1 + 0 \cdot 2} < 1$$
0 < 1
so the inequality is always executed