Given the inequality: sin(3x)≥22 To solve this inequality, we must first solve the corresponding equation: sin(3x)=22 Solve: Given the equation sin(3x)=22 - this is the simplest trigonometric equation This equation is transformed to 3x=2πn+asin(22) 3x=2πn−asin(22)+π Or 3x=2πn+4π 3x=2πn+43π , where n - is a integer Divide both parts of the equation by 3 x1=32πn+12π x2=32πn+4π x1=32πn+12π x2=32πn+4π This roots x1=32πn+12π x2=32πn+4π is the points with change the sign of the inequality expression. First define with the sign to the leftmost point: x0≤x1 For example, let's take the point x0=x1−101 = (32πn+12π)+−101 = 32πn−101+12π substitute to the expression sin(3x)≥22 sin(3(32πn−101+12π))≥22