7√x+2>=2x inequation

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7*\/ x  + 2 >= 2*x

$$7 \sqrt{x} + 2 \geq 2 x$$

7*sqrt(x) + 2 >= 2*x

Solving inequality on a graph

Rapid solution 2 [src]

             ____ 
    57   7*\/ 65  
[0, -- + --------]
    8       8

$$x\ in\ \left[0, \frac{7 \sqrt{65}}{8} + \frac{57}{8}\right]$$

x in Interval(0, 7*sqrt(65)/8 + 57/8)

Rapid solution [src]

   /                      ____\
   |             57   7*\/ 65 |
And|0 <= x, x <= -- + --------|
   \             8       8    /

$$0 \leq x \wedge x \leq \frac{7 \sqrt{65}}{8} + \frac{57}{8}$$

(0 <= x)∧(x <= 57/8 + 7*sqrt(65)/8)