Mister Exam

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Inequation:
9^x<=-x+1
(2*x)^2-4*(x+2)>=0
(x^2—16)*log0.5(x)>=0
(-x/8)+1/3>0
Identical expressions
seven ^(-|x- three |)*log(two , six *x-(x^ two)+ seven)>= one
7 to the power of ( minus module of x minus 3|) multiply by logarithm of (2,6 multiply by x minus (x squared ) plus 7) greater than or equal to 1
seven to the power of ( minus module of x minus three |) multiply by logarithm of (two , six multiply by x minus (x to the power of two) plus seven) greater than or equal to one
7(-|x-3|)*log(2,6*x-(x2)+7)>=1
7-|x-3|*log2,6*x-x2+7>=1
7^(-|x-3|)*log(2,6*x-(x²)+7)>=1
7 to the power of (-|x-3|)*log(2,6*x-(x to the power of 2)+7)>=1
7^(-|x-3|)log(2,6x-(x^2)+7)>=1
7(-|x-3|)log(2,6x-(x2)+7)>=1
7-|x-3|log2,6x-x2+7>=1
7^-|x-3|log2,6x-x^2+7>=1
Similar expressions
7^(-|x-3|)*log(2,6*x+(x^2)+7)>=1
7^(|x-3|)*log(2,6*x-(x^2)+7)>=1
7^(-|x-3|)*log(2,6*x-(x^2)-7)>=1
7^(-|x+3|)*log(2,6*x-(x^2)+7)>=1

7^(-|x-3|)log(2,6x-(x^2)+7)>=1 inequation

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 -|x - 3|    /13*x    2    \     
7        *log|---- - x  + 7| >= 1
             \ 5           /

$$7^{- \left|{x - 3}\right|} \log{\left(\left(- x^{2} + \frac{13 x}{5}\right) + 7 \right)} \geq 1$$

7^(-|x - 3|)*log(-x^2 + 13*x/5 + 7) >= 1

Solving inequality on a graph

7^(-|x-3|)*log(2,6*x-(x^2)+7)>=1 inequation