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Inequation:
(29/2)x-3>9x+8
(1/(x-1))-(1/(x-2))=>(1/(x+1))-(1/(x+2))
(x^2(x+2))/(2x+3)<=0
7x<-3
Identical expressions
(one /(x- one))-(one /(x- two))=>(one /(x+ one))-(one /(x+ two))
(1 divide by (x minus 1)) minus (1 divide by (x minus 2)) equally greater than (1 divide by (x plus 1)) minus (1 divide by (x plus 2))
(one divide by (x minus one)) minus (one divide by (x minus two)) equally greater than (one divide by (x plus one)) minus (one divide by (x plus two))
1/x-1-1/x-2=>1/x+1-1/x+2
(1 divide by (x-1))-(1 divide by (x-2))=>(1 divide by (x+1))-(1 divide by (x+2))
Similar expressions
(1/(x-1))+(1/(x-2))=>(1/(x+1))-(1/(x+2))
(1/(x-1))-(1/(x-2))=>(1/(x-1))-(1/(x+2))
(1/(x-1))-(1/(x-2))=>(1/(x+1))+(1/(x+2))
(1/(x-1))-(1/(x-2))=>(1/(x+1))-(1/(x-2))
(1/(x-1))-(1/(x+2))=>(1/(x+1))-(1/(x+2))
(1/(x+1))-(1/(x-2))=>(1/(x+1))-(1/(x+2))

(1/(x-1))-(1/(x-2))=>(1/(x+1))-(1/(x+2)) inequation

You have entered [src]

  1       1        1       1  
----- - ----- >= ----- - -----
x - 1   x - 2    x + 1   x + 2

$$\frac{1}{x - 1} - \frac{1}{x - 2} \geq - \frac{1}{x + 2} + \frac{1}{x + 1}$$

1/(x - 1) - 1/(x - 2) >= -1/(x + 2) + 1/(x + 1)

Solving inequality on a graph

Rapid solution [src]

Or(And(-2 < x, x < -1), And(1 < x, x < 2))

$$\left(-2 < x \wedge x < -1\right) \vee \left(1 < x \wedge x < 2\right)$$

((-2 < x)∧(x < -1))∨((1 < x)∧(x < 2))

Rapid solution 2 [src]

(-2, -1) U (1, 2)

$$x\ in\ \left(-2, -1\right) \cup \left(1, 2\right)$$

x in Union(Interval.open(-2, -1), Interval.open(1, 2))