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How to use it?
- Inequation:
- (3x+5)(1-x)(x+1)^2>=0
- (x+1)*log(x+4)<0
- 25^x+0,5+4•5^x-1>=0
- (2x-7)\(4-x)>=0
- Limit of the function:
-
-4+2*x
-
Identical expressions
- - four + two *x> zero
- minus 4 plus 2 multiply by x greater than 0
- minus four plus two multiply by x greater than zero
- -4+2x>0
-
Similar expressions
- 14-(4+2)*x>1+x
- ((2/(x-4))^4)-(((1/4)*x^2))-((4+2*x))>0
- ((x^2-6-x)/(x^2-4)+(2x-3)/(2-x)+(x^2)/x)<=0
- 31+5x>-(4+2x)
- 4+2*x>0
- -4-2*x>0
-4+2*x>0 inequation
The solution
Detail solution
Given the inequality:
$$2 x - 4 > 0$$
To solve this inequality, we must first solve the corresponding equation:
$$2 x - 4 = 0$$
Solve:
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$2 x = 4$$
Divide both parts of the equation by 2
$$x_{1} = 2$$
$$x_{1} = 2$$
This roots
$$x_{1} = 2$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + 2$$
=
$$\frac{19}{10}$$
substitute to the expression
$$2 x - 4 > 0$$
$$-4 + \frac{2 \cdot 19}{10} > 0$$
Then
$$x < 2$$
no execute
the solution of our inequality is:
$$x > 2$$
$$2 x - 4 > 0$$
To solve this inequality, we must first solve the corresponding equation:
$$2 x - 4 = 0$$
Solve:
Given the linear equation:
-4+2*x = 0
Move free summands (without x)
from left part to right part, we given:
$$2 x = 4$$
Divide both parts of the equation by 2
x = 4 / (2)
$$x_{1} = 2$$
$$x_{1} = 2$$
This roots
$$x_{1} = 2$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + 2$$
=
$$\frac{19}{10}$$
substitute to the expression
$$2 x - 4 > 0$$
$$-4 + \frac{2 \cdot 19}{10} > 0$$
-1/5 > 0
Then
$$x < 2$$
no execute
the solution of our inequality is:
$$x > 2$$
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Solving inequality on a graph