/ 2 \ log(1/5)*\x + 6*x + 8/ > log(1/5)*(5*x + 10)
(x^2 + 6*x + 8)*log(1/5) > (5*x + 10)*log(1/5)
(-2, 1)
x in Interval.open(-2, 1)
And(-2 < x, x < 1)
(-2 < x)∧(x < 1)