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Inequation
:
log0.5^2(x)+log0.5(x-2)<=0
x^2*log16(x)>=log16(x)^5+(x)*log2(x)
2/log2(2x-2)+3/log2(4x-4)<=8/log3(27)+log2(x-1)
3*lg^2(x-8)/(lg^2(x-4))>=2
Canonical form
:
=0
Identical expressions
log zero . five ^ two (x)+log0. five (x- two)<=0
logarithm of 0.5 squared (x) plus logarithm of 0.5(x minus 2) less than or equal to 0
logarithm of zero . five to the power of two (x) plus logarithm of 0. five (x minus two) less than or equal to 0
log0.52(x)+log0.5(x-2)<=0
log0.52x+log0.5x-2<=0
log0.5²(x)+log0.5(x-2)<=0
log0.5 to the power of 2(x)+log0.5(x-2)<=0
log0.5^2x+log0.5x-2<=0
log0.5^2(x)+log0.5(x-2)<=O
Similar expressions
log0.5^2(x)+log0.5(x+2)<=0
log0.5^2(x)-log0.5(x-2)<=0
Solving inequalities
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log0.5^2(x)+log0.5(x-2)<=0
log0.5^2(x)+log0.5(x-2)<=0 inequation
+ inequation
Solve the inequality!
A inequation with variable
The solution
You have entered
[src]
2 log (0.5)*x + log(0.0)*5*(x - 2) <= 0
$$x \log{\left(0.5 \right)}^{2} + \log{\left(0.0 \right)} 5 \left(x - 2\right) \leq 0$$
x*log(0.5)^2 + log(0.0)*5*(x - 1*2) <= 0