Given the inequality:
$$\frac{\log{\left(x \right)}}{\log{\left(\frac{3}{5} \right)}} > \frac{1}{2}$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{\log{\left(x \right)}}{\log{\left(\frac{3}{5} \right)}} = \frac{1}{2}$$
Solve:
Given the equation
$$\frac{\log{\left(x \right)}}{\log{\left(\frac{3}{5} \right)}} = \frac{1}{2}$$
$$\frac{\log{\left(x \right)}}{\log{\left(\frac{3}{5} \right)}} = \frac{1}{2}$$
Let's divide both parts of the equation by the multiplier of log =1/log(3/5)
$$\log{\left(x \right)} = \frac{\log{\left(\frac{3}{5} \right)}}{2}$$
This equation is of the form:
log(v)=p
By definition log
v=e^p
then
$$x = e^{\frac{1}{2 \frac{1}{\log{\left(\frac{3}{5} \right)}}}}$$
simplify
$$x = \frac{\sqrt{15}}{5}$$
$$x_{1} = \frac{\sqrt{15}}{5}$$
$$x_{1} = \frac{\sqrt{15}}{5}$$
This roots
$$x_{1} = \frac{\sqrt{15}}{5}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + \frac{\sqrt{15}}{5}$$
=
$$- \frac{1}{10} + \frac{\sqrt{15}}{5}$$
substitute to the expression
$$\frac{\log{\left(x \right)}}{\log{\left(\frac{3}{5} \right)}} > \frac{1}{2}$$
$$\frac{\log{\left(- \frac{1}{10} + \frac{\sqrt{15}}{5} \right)}}{\log{\left(\frac{3}{5} \right)}} > \frac{1}{2}$$
/ ____\
| 1 \/ 15 |
log|- -- + ------|
\ 10 5 / > 1/2
------------------
log(3/5)
the solution of our inequality is:
$$x < \frac{\sqrt{15}}{5}$$
_____
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x1