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Solving inequalities/ log2(x^2+5x)+log0,5(x/8)+1>=log2(x^2+4x-5)

log2(x^2+5x)+log0,5(x/8)+1>=log2(x^2+4x-5) inequation

A inequation with variable

The solution

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   / 2      \                          / 2          \
log\x  + 5*x/              x        log\x  + 4*x - 5/
------------- + log(0.0)*5*- + 1 >= -----------------
    log(2)                 8              log(2)
$$\left(5 \log{\left(0.0 \right)} \frac{x}{8} + \frac{\log{\left(x^{2} + 5 x \right)}}{\log{\left(2 \right)}}\right) + 1 \geq \frac{\log{\left(\left(x^{2} + 4 x\right) - 5 \right)}}{\log{\left(2 \right)}}$$ 
(5*log(0.0))*(x/8) + log(x^2 + 5*x)/log(2) + 1 >= log(x^2 + 4*x - 5)/log(2)
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