Mister Exam

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How to use it?
Inequation:
14logax+19/logax^2+4<1
−(3x+2)+(x−7)>0
2log_2^2(x)-3log_2(x)+2<=0
(5/(sqrtx-1)-5)>=-1
Identical expressions
log three (x^ four - four *x^ two + four)+3=>log9(two ^-x2)
logarithm of 3(x to the power of 4 minus 4 multiply by x squared plus 4) plus 3 equally greater than logarithm of 9(2 to the power of minus x2)
logarithm of three (x to the power of four minus four multiply by x to the power of two plus four) plus 3 equally greater than logarithm of 9(two to the power of minus x2)
log3(x4-4*x2+4)+3=>log9(2-x2)
log3x4-4*x2+4+3=>log92-x2
log3(x⁴-4*x²+4)+3=>log9(2^-x2)
log3(x to the power of 4-4*x to the power of 2+4)+3=>log9(2 to the power of -x2)
log3(x^4-4x^2+4)+3=>log9(2^-x2)
log3(x4-4x2+4)+3=>log9(2-x2)
log3x4-4x2+4+3=>log92-x2
log3x^4-4x^2+4+3=>log92^-x2
Similar expressions
log3(x^4-4*x^2+4)+3=>log9(2^+x2)
log3(x^4+4*x^2+4)+3=>log9(2^-x2)
log3(x^4-4*x^2-4)+3=>log9(2^-x2)
log3(x^4-4*x^2+4)-3=>log9(2^-x2)
What you mean?
log(x^4 - 4*x^2 + 4)/log(3) + 3 >= log(2^(-x2))/log(9)
log(x^4 - 4*x^2 + 4)/log(3) + 3 >= log(2^(-x^2))/log(9)
log(x^4 - 4*x^2 + 4)/log(3) + 3 >= log(2^(-x^2))/log(9)

log3(x^4-4*x^2+4)+3=>log9(2^-x2) inequation

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   / 4      2    \           / -x2\
log\x  - 4*x  + 4/        log\2   /
------------------ + 3 >= ---------
      log(3)                log(9)

$$\frac{\log{\left(x^{4} - 4 x^{2} + 4 \right)}}{\log{\left(3 \right)}} + 3 \geq \frac{\log{\left(2^{- x_{2}} \right)}}{\log{\left(9 \right)}}$$

log(x^4 - 4*x^2 + 4)/log(3) + 3 >= log(2^(-x2))/log(9)