Mister Exam

Lang:

How to use it?
Inequation:
log(3x–3)3+log(x–1)^2(27)>=2
log2(x^2+5x)+log0,5(x/8)+1>=log2(x^2+4x-5)
3(2x-4)<=-5(2-3x)
x^2+9y^4+1=>-3xy^2-x+3y^2
Identical expressions
log(three x– three)3+log(x– one)^ two (twenty-seven)>= two
logarithm of (3x–3)3 plus logarithm of (x–1) squared (27) greater than or equal to 2
logarithm of (three x– three)3 plus logarithm of (x– one) to the power of two (twenty minus seven) greater than or equal to two
log(3x–3)3+log(x–1)2(27)>=2
log3x–33+logx–1227>=2
log(3x–3)3+log(x–1)²(27)>=2
log(3x–3)3+log(x–1) to the power of 2(27)>=2
log3x–33+logx–1^227>=2
Similar expressions
log(3x–3)3-log(x–1)^2(27)>=2

log(3x–3)3+log(x–1)^2(27)>=2 inequation

You have entered [src]

                    2               
log(3*x - 3)*3 + log (x - 1)*27 >= 2

$$27 \log{\left(x - 1 \right)}^{2} + 3 \log{\left(3 x - 3 \right)} \geq 2$$

27*log(x - 1)^2 + 3*log(3*x - 3) >= 2

Solving inequality on a graph