Given the inequality:
$$\frac{\log{\left(1 \right)}}{2} \left(x + 1\right) \geq -1$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{\log{\left(1 \right)}}{2} \left(x + 1\right) = -1$$
Solve:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
x0 = 0
$$\frac{\log{\left(1 \right)}}{2} \geq -1$$
0 >= -1
so the inequality is always executed