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log1/2(x+1)≥-1 inequation

A inequation with variable

The solution

You have entered [src]
log(1)              
------*(x + 1) >= -1
  2                 
$$\frac{\log{\left(1 \right)}}{2} \left(x + 1\right) \geq -1$$
(log(1)/2)*(x + 1) >= -1
Detail solution
Given the inequality:
$$\frac{\log{\left(1 \right)}}{2} \left(x + 1\right) \geq -1$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{\log{\left(1 \right)}}{2} \left(x + 1\right) = -1$$
Solve:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
x0 = 0

$$\frac{\log{\left(1 \right)}}{2} \geq -1$$
0 >= -1

so the inequality is always executed
Rapid solution [src]
And(-oo < x, x < oo)
$$-\infty < x \wedge x < \infty$$
(-oo < x)∧(x < oo)
Rapid solution 2 [src]
(-oo, oo)
$$x\ in\ \left(-\infty, \infty\right)$$
x in Interval(-oo, oo)