Mister Exam
Other calculators
- Square Inequality Step-by-Step
- Inequality with the module Step by Step
- Logarithmic inequality online
-
How to use it?
- Inequation:
-
sin2xcosx-cos2xsinx>=sqrt(2)/2
- (2sqrt(x+3))/(x+1)<=(3sqrt(x+3))/(x+2)
- log2/x(256)>=log2(2x)
- log0,5(2x^2+3x+1)=>2log0,5(x-1)
-
Identical expressions
- log0, five (two x^2+3x+ one)=>2log0, five (x- one)
- logarithm of 0,5(2x squared plus 3x plus 1) equally greater than 2 logarithm of 0,5(x minus 1)
- logarithm of 0, five (two x squared plus 3x plus one) equally greater than 2 logarithm of 0, five (x minus one)
- log0,5(2x2+3x+1)=>2log0,5(x-1)
- log0,52x2+3x+1=>2log0,5x-1
- log0,5(2x²+3x+1)=>2log0,5(x-1)
- log0,5(2x to the power of 2+3x+1)=>2log0,5(x-1)
- log0,52x^2+3x+1=>2log0,5x-1
-
Similar expressions
- log0,5(2x^2+3x-1)=>2log0,5(x-1)
- log0,5(2x^2+3x+1)=>2log0,5(x+1)
- log0,5(2x^2-3x+1)=>2log0,5(x-1)
log0,5(2x^2+3x+1)=>2log0,5(x-1) inequation
The solution
You have entered
[src]
/ 2 \ log(0.0)*5*\2*x + 3*x + 1/ >= 2*log(0.0)*5*(x - 1)
$$5 \log{\left(0.0 \right)} \left(\left(2 x^{2} + 3 x\right) + 1\right) \geq 5 \cdot 2 \log{\left(0.0 \right)} \left(x - 1\right)$$
(5*log(0.0))*(2*x^2 + 3*x + 1) >= (5*(2*log(0.0)))*(x - 1)