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How to use it?
- Inequation:
- (0,1)^(x^2-4x-15/x+1)>=0,001
- lg(6)+x*lg(5)>=x+lg(2^x+1)
- log0,4(2*x-5)>log0,4(x+1)
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(3^(2x-1)+3^(2x-2)-3^(2x-4))<=315
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Identical expressions
- lg(six)+x*lg(five)>=x+lg(two ^x+ one)
- lg(6) plus x multiply by lg(5) greater than or equal to x plus lg(2 to the power of x plus 1)
- lg(six) plus x multiply by lg(five) greater than or equal to x plus lg(two to the power of x plus one)
- lg(6)+x*lg(5)>=x+lg(2x+1)
- lg6+x*lg5>=x+lg2x+1
- lg(6)+xlg(5)>=x+lg(2^x+1)
- lg(6)+xlg(5)>=x+lg(2x+1)
- lg6+xlg5>=x+lg2x+1
- lg6+xlg5>=x+lg2^x+1
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Similar expressions
- lg(6)-x*lg(5)>=x+lg(2^x+1)
- lg(6)+x*lg(5)>=x+lg(2^x-1)
- lg(6)+x*lg(5)>=x-lg(2^x+1)
lg(6)+x*lg(5)>=x+lg(2^x+1) inequation
The solution
You have entered
[src]
/ x \ log(6) + x*log(5) >= x + log\2 + 1/
$$x \log{\left(5 \right)} + \log{\left(6 \right)} \geq x + \log{\left(2^{x} + 1 \right)}$$
x*log(5) + log(6) >= x + log(2^x + 1)
Solving inequality on a graph