Given the inequality:
$$\frac{5 - 6 x}{2 x + 5} < 1$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{5 - 6 x}{2 x + 5} = 1$$
Solve:
Given the equation:
$$\frac{5 - 6 x}{2 x + 5} = 1$$
Multiply the equation sides by the denominator 5 + 2*x
we get:
$$5 - 6 x = 2 x + 5$$
Move free summands (without x)
from left part to right part, we given:
$$- 6 x = 2 x$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-8\right) x = 0$$
Divide both parts of the equation by -8
x = 0 / (-8)
$$x_{1} = 0$$
$$x_{1} = 0$$
This roots
$$x_{1} = 0$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10}$$
=
$$- \frac{1}{10}$$
substitute to the expression
$$\frac{5 - 6 x}{2 x + 5} < 1$$
$$\frac{5 - \frac{\left(-1\right) 6}{10}}{\frac{\left(-1\right) 2}{10} + 5} < 1$$
7/6 < 1
but
7/6 > 1
Then
$$x < 0$$
no execute
the solution of our inequality is:
$$x > 0$$
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