Given the inequality:
$$\cot{\left(\frac{x}{2} - \frac{\pi}{4} \right)} \leq \frac{\left(-1\right) \sqrt{3}}{3}$$
To solve this inequality, we must first solve the corresponding equation:
$$\cot{\left(\frac{x}{2} - \frac{\pi}{4} \right)} = \frac{\left(-1\right) \sqrt{3}}{3}$$
Solve:
$$x_{1} = - \frac{\pi}{6}$$
$$x_{1} = - \frac{\pi}{6}$$
This roots
$$x_{1} = - \frac{\pi}{6}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} \leq x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{\pi}{6} - \frac{1}{10}$$
=
$$- \frac{\pi}{6} - \frac{1}{10}$$
substitute to the expression
$$\cot{\left(\frac{x}{2} - \frac{\pi}{4} \right)} \leq \frac{\left(-1\right) \sqrt{3}}{3}$$
$$\cot{\left(- \frac{\pi}{4} + \frac{- \frac{\pi}{6} - \frac{1}{10}}{2} \right)} \leq \frac{\left(-1\right) \sqrt{3}}{3}$$
___
/1 pi\ -\/ 3
-cot|-- + --| <= -------
\20 3 / 3
but
___
/1 pi\ -\/ 3
-cot|-- + --| >= -------
\20 3 / 3
Then
$$x \leq - \frac{\pi}{6}$$
no execute
the solution of our inequality is:
$$x \geq - \frac{\pi}{6}$$
_____
/
-------•-------
x1