Given the inequality:
$$\cos{\left(\frac{x}{5} + \frac{2 \pi}{3} \right)} < \frac{\left(-1\right) \sqrt{2}}{2}$$
To solve this inequality, we must first solve the corresponding equation:
$$\cos{\left(\frac{x}{5} + \frac{2 \pi}{3} \right)} = \frac{\left(-1\right) \sqrt{2}}{2}$$
Solve:
Given the equation
$$\cos{\left(\frac{x}{5} + \frac{2 \pi}{3} \right)} = \frac{\left(-1\right) \sqrt{2}}{2}$$
- this is the simplest trigonometric equation
Divide both parts of the equation by -1
The equation is transformed to
$$\sin{\left(\frac{x}{5} + \frac{\pi}{6} \right)} = \frac{\sqrt{2}}{2}$$
This equation is transformed to
$$\frac{x}{5} + \frac{\pi}{6} = 2 \pi n + \operatorname{asin}{\left(\frac{\sqrt{2}}{2} \right)}$$
$$\frac{x}{5} + \frac{\pi}{6} = 2 \pi n - \operatorname{asin}{\left(\frac{\sqrt{2}}{2} \right)} + \pi$$
Or
$$\frac{x}{5} + \frac{\pi}{6} = 2 \pi n + \frac{\pi}{4}$$
$$\frac{x}{5} + \frac{\pi}{6} = 2 \pi n + \frac{3 \pi}{4}$$
, where n - is a integer
Move
$$\frac{\pi}{6}$$
to right part of the equation
with the opposite sign, in total:
$$\frac{x}{5} = 2 \pi n + \frac{\pi}{12}$$
$$\frac{x}{5} = 2 \pi n + \frac{7 \pi}{12}$$
Divide both parts of the equation by
$$\frac{1}{5}$$
$$x_{1} = 10 \pi n + \frac{5 \pi}{12}$$
$$x_{2} = 10 \pi n + \frac{35 \pi}{12}$$
$$x_{1} = 10 \pi n + \frac{5 \pi}{12}$$
$$x_{2} = 10 \pi n + \frac{35 \pi}{12}$$
This roots
$$x_{1} = 10 \pi n + \frac{5 \pi}{12}$$
$$x_{2} = 10 \pi n + \frac{35 \pi}{12}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$\left(10 \pi n + \frac{5 \pi}{12}\right) + - \frac{1}{10}$$
=
$$10 \pi n - \frac{1}{10} + \frac{5 \pi}{12}$$
substitute to the expression
$$\cos{\left(\frac{x}{5} + \frac{2 \pi}{3} \right)} < \frac{\left(-1\right) \sqrt{2}}{2}$$
$$\cos{\left(\frac{10 \pi n - \frac{1}{10} + \frac{5 \pi}{12}}{5} + \frac{2 \pi}{3} \right)} < \frac{\left(-1\right) \sqrt{2}}{2}$$
___
/ 1 pi \ -\/ 2
-sin|- -- + -- + 2*pi*n| < -------
\ 50 4 / 2
but
___
/ 1 pi \ -\/ 2
-sin|- -- + -- + 2*pi*n| > -------
\ 50 4 / 2
Then
$$x < 10 \pi n + \frac{5 \pi}{12}$$
no execute
one of the solutions of our inequality is:
$$x > 10 \pi n + \frac{5 \pi}{12} \wedge x < 10 \pi n + \frac{35 \pi}{12}$$
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/ \
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x1 x2