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Inequation
:
log2(1-x)>log2(2x-8)
y^2-4*x+8>0
4x−3x**2−9≤0
(x-4)^2>16-x^2
Derivative of
:
arctgx
Integral of d{x}
:
arctgx
Identical expressions
arctgx<x-x^ three / six
arctgx less than x minus x cubed divide by 6
arctgx less than x minus x to the power of three divide by six
arctgx<x-x3/6
arctgx<x-x³/6
arctgx<x-x to the power of 3/6
arctgx<x-x^3 divide by 6
Similar expressions
arctgx<x+x^3/6
arctg(x)>x-(x^3)/3
arccos(x)>arctg(x)
log(x^2+1)<x*arctg(x)
Solving inequalities
/
arctgx
arctgx
+ inequation
Solve the inequality!
A inequation with variable
The solution
You have entered
[src]
3 x acot(x) < x - -- 6
$$\operatorname{acot}{\left(x \right)} < - \frac{x^{3}}{6} + x$$
acot(x) < -x^3/6 + x