Mister Exam

Lang:

How to use it?
Inequation:
2(x-8)>5x-2
1+8x<9
-3x^2+x-2<=0
2^log(10)*(x^2-4)>=(x+2)^log(10)*2
Integral of d{x}:
3x+4
Canonical form:
3x+4
Sum of series:
3x+4
Identical expressions
(9x^ two -12x- three)/(3x- four)+(12x- twenty-five)/(3x- eight)>3x+ four
(9x squared minus 12x minus 3) divide by (3x minus 4) plus (12x minus 25) divide by (3x minus 8) greater than 3x plus 4
(9x to the power of two minus 12x minus three) divide by (3x minus four) plus (12x minus twenty minus five) divide by (3x minus eight) greater than 3x plus four
(9x2-12x-3)/(3x-4)+(12x-25)/(3x-8)>3x+4
9x2-12x-3/3x-4+12x-25/3x-8>3x+4
(9x²-12x-3)/(3x-4)+(12x-25)/(3x-8)>3x+4
(9x to the power of 2-12x-3)/(3x-4)+(12x-25)/(3x-8)>3x+4
9x^2-12x-3/3x-4+12x-25/3x-8>3x+4
(9x^2-12x-3) divide by (3x-4)+(12x-25) divide by (3x-8)>3x+4
Similar expressions
(9x^2-12x-3)/(3x+4)+(12x-25)/(3x-8)>3x+4
(9x^2-12x-3)/(3x-4)+(12x-25)/(3x+8)>3x+4
(9x^2+12x-3)/(3x-4)+(12x-25)/(3x-8)>3x+4
-(2-3x)+4(6+x)≥1
(9x^2-12x+3)/(3x-4)+(12x-25)/(3x-8)>3x+4
(9x^2-12x-3)/(3x-4)+(12x-25)/(3x-8)>3x-4
(9x^2-12x-3)/(3x-4)+(12x+25)/(3x-8)>3x+4
(9x^2-12x-3)/(3x-4)-(12x-25)/(3x-8)>3x+4

(9x^2-12x-3)/(3x-4)+(12x-25)/(3x-8)>3x+4 inequation

You have entered [src]

   2                                 
9*x  - 12*x - 3   12*x - 25          
--------------- + --------- > 3*x + 4
    3*x - 4        3*x - 8

$$\frac{\left(9 x^{2} - 12 x\right) - 3}{3 x - 4} + \frac{12 x - 25}{3 x - 8} > 3 x + 4$$

(9*x^2 - 12*x - 3)/(3*x - 4) + (12*x - 25)/(3*x - 8) > 3*x + 4

Solving inequality on a graph

Rapid solution 2 [src]

(1/3, 4/3) U (8/3, oo)

$$x\ in\ \left(\frac{1}{3}, \frac{4}{3}\right) \cup \left(\frac{8}{3}, \infty\right)$$

x in Union(Interval.open(1/3, 4/3), Interval.open(8/3, oo))

Rapid solution [src]

Or(And(1/3 < x, x < 4/3), And(8/3 < x, x < oo))

$$\left(\frac{1}{3} < x \wedge x < \frac{4}{3}\right) \vee \left(\frac{8}{3} < x \wedge x < \infty\right)$$

((1/3 < x)∧(x < 4/3))∨((8/3 < x)∧(x < oo))