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-
How to use it?
- Inequation:
- x^2log625(2-x)≥log5(x^2-4x+4)
- 6^x^2-x-1*7^x-2>=6
-
6x-5<13
- sqrt(6x-11)<7
- Graphing y =:
- 6x-5
- Sum of series:
-
13
- Derivative of:
-
13
- Canonical form:
- 13
-
Identical expressions
- 6x- five < thirteen
- 6x minus 5 less than 13
- 6x minus five less than thirteen
-
Similar expressions
- (x^2+1)(x+6)(x-5)<=0
- 40-28*16^x-2*4^x/(16^x-5*4^x+4)<=16^x+3*4^(x+1)+10
- 3*log11(x^2+8*x-9)<=4+log(11,(x-1)^3/(x+9))
- 6x+5<13
6x-5<13 inequation
The solution
Detail solution
Given the inequality:
$$6 x - 5 < 13$$
To solve this inequality, we must first solve the corresponding equation:
$$6 x - 5 = 13$$
Solve:
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$6 x = 18$$
Divide both parts of the equation by 6
$$x_{1} = 3$$
$$x_{1} = 3$$
This roots
$$x_{1} = 3$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + 3$$
=
$$\frac{29}{10}$$
substitute to the expression
$$6 x - 5 < 13$$
$$\left(-1\right) 5 + 6 \cdot \frac{29}{10} < 13$$
the solution of our inequality is:
$$x < 3$$
$$6 x - 5 < 13$$
To solve this inequality, we must first solve the corresponding equation:
$$6 x - 5 = 13$$
Solve:
Given the linear equation:
6*x-5 = 13
Move free summands (without x)
from left part to right part, we given:
$$6 x = 18$$
Divide both parts of the equation by 6
x = 18 / (6)
$$x_{1} = 3$$
$$x_{1} = 3$$
This roots
$$x_{1} = 3$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + 3$$
=
$$\frac{29}{10}$$
substitute to the expression
$$6 x - 5 < 13$$
$$\left(-1\right) 5 + 6 \cdot \frac{29}{10} < 13$$
62/5 < 13
the solution of our inequality is:
$$x < 3$$
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x_1
Solving inequality on a graph
The graph