Mister Exam
Other calculators
- Square Inequality Step-by-Step
- Inequality with the module Step by Step
- Logarithmic inequality online
-
How to use it?
- Inequation:
- -8x+7,8_<-12,6x+28,5
- x^2-8x+15<=0
- 6x<45
- 13x+6>18x
- Integral of d{x}:
-
6x
-
45
- Derivative of:
-
6x
- Equation:
- 6x
- Sum of series:
-
45
- Expression:
- 45
-
Identical expressions
- 6x< forty-five
- 6x less than 45
- 6x less than forty minus five
-
Similar expressions
- x^4-4x^3+4x^2/(x+4)^5*(5-x)^3<=0
- 5^x/6+3*25^x-2*5^x*5-25/(25^x-24*5^x-25)<5/6
- (3x-6)(x-3)(x-5)>=0
- 8(x+1)-7<=6(x-2)
- log(x-1)(4^(log3(x))-6*x^(log3(2))+10)<=0
- 25^x+4*5^x-5≤0
6x<45 inequation
The solution
Detail solution
Given the inequality:
$$6 x < 45$$
To solve this inequality, we must first solve the corresponding equation:
$$6 x = 45$$
Solve:
Given the linear equation:
Divide both parts of the equation by 6
$$x_{1} = \frac{15}{2}$$
$$x_{1} = \frac{15}{2}$$
This roots
$$x_{1} = \frac{15}{2}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + \frac{15}{2}$$
=
$$\frac{37}{5}$$
substitute to the expression
$$6 x < 45$$
$$\frac{6 \cdot 37}{5} < 45$$
the solution of our inequality is:
$$x < \frac{15}{2}$$
$$6 x < 45$$
To solve this inequality, we must first solve the corresponding equation:
$$6 x = 45$$
Solve:
Given the linear equation:
6*x = 45
Divide both parts of the equation by 6
x = 45 / (6)
$$x_{1} = \frac{15}{2}$$
$$x_{1} = \frac{15}{2}$$
This roots
$$x_{1} = \frac{15}{2}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + \frac{15}{2}$$
=
$$\frac{37}{5}$$
substitute to the expression
$$6 x < 45$$
$$\frac{6 \cdot 37}{5} < 45$$
222/5 < 45
the solution of our inequality is:
$$x < \frac{15}{2}$$
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x1
Solving inequality on a graph
Rapid solution
[src]
And(-oo < x, x < 15/2)
$$-\infty < x \wedge x < \frac{15}{2}$$
(-oo < x)∧(x < 15/2)
Rapid solution 2
[src]
(-oo, 15/2)
$$x\ in\ \left(-\infty, \frac{15}{2}\right)$$
x in Interval.open(-oo, 15/2)