Mister Exam
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- Square Inequality Step-by-Step
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-
How to use it?
- Inequation:
- log1/4(x-3)>=log1/4(2x+4)
- |z+i|+|z-i|<4
- a^4+b^4+c^4+d^4≥4abcd
- 4x+7<11
- Graphing y =:
- 4x+7
- Derivative of:
- 11
- Sum of series:
-
11
- Integral of d{x}:
-
11
-
Identical expressions
- 4x+ seven < eleven
- 4x plus 7 less than 11
- 4x plus seven less than eleven
-
Similar expressions
- 4x-7<11
- (x+1)^5(x+2)^4(x+7)^5(x-4)^9(x^3-1)<0
- 24*x+7<=22*x-13
4x+7<11 inequation
The solution
Detail solution
Given the inequality:
$$4 x + 7 < 11$$
To solve this inequality, we must first solve the corresponding equation:
$$4 x + 7 = 11$$
Solve:
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$4 x = 4$$
Divide both parts of the equation by 4
$$x_{1} = 1$$
$$x_{1} = 1$$
This roots
$$x_{1} = 1$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + 1$$
=
$$\frac{9}{10}$$
substitute to the expression
$$4 x + 7 < 11$$
$$\frac{4 \cdot 9}{10} + 7 < 11$$
the solution of our inequality is:
$$x < 1$$
$$4 x + 7 < 11$$
To solve this inequality, we must first solve the corresponding equation:
$$4 x + 7 = 11$$
Solve:
Given the linear equation:
4*x+7 = 11
Move free summands (without x)
from left part to right part, we given:
$$4 x = 4$$
Divide both parts of the equation by 4
x = 4 / (4)
$$x_{1} = 1$$
$$x_{1} = 1$$
This roots
$$x_{1} = 1$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + 1$$
=
$$\frac{9}{10}$$
substitute to the expression
$$4 x + 7 < 11$$
$$\frac{4 \cdot 9}{10} + 7 < 11$$
53/5 < 11
the solution of our inequality is:
$$x < 1$$
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Solving inequality on a graph