Given the inequality:
$$\frac{3 x + 2}{5 x - 1} < 0$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{3 x + 2}{5 x - 1} = 0$$
Solve:
Given the equation:
$$\frac{3 x + 2}{5 x - 1} = 0$$
Multiply the equation sides by the denominator -1 + 5*x
we get:
$$3 x + 2 = 0$$
Move free summands (without x)
from left part to right part, we given:
$$3 x = -2$$
Divide both parts of the equation by 3
x = -2 / (3)
$$x_{1} = - \frac{2}{3}$$
$$x_{1} = - \frac{2}{3}$$
This roots
$$x_{1} = - \frac{2}{3}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{2}{3} + - \frac{1}{10}$$
=
$$- \frac{23}{30}$$
substitute to the expression
$$\frac{3 x + 2}{5 x - 1} < 0$$
$$\frac{\frac{\left(-23\right) 3}{30} + 2}{\frac{\left(-23\right) 5}{30} - 1} < 0$$
9/145 < 0
but
9/145 > 0
Then
$$x < - \frac{2}{3}$$
no execute
the solution of our inequality is:
$$x > - \frac{2}{3}$$
_____
/
-------ο-------
x1