10а+19≥7(2а-3) inequation

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10*a + 19 >= 7*(2*a - 3)

$$10 a + 19 \geq 7 \left(2 a - 3\right)$$

10*a + 19 >= 7*(2*a - 3)

Rapid solution [src]

And(a <= 10, -oo < a)

$$a \leq 10 \wedge -\infty < a$$

(a <= 10)∧(-oo < a)

Rapid solution 2 [src]

(-oo, 10]

$$x\ in\ \left(-\infty, 10\right]$$

x in Interval(-oo, 10)