Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- -7*x-20*y=-5
- 5*x-6*y=3
- -20*x+17*y=-16
- -8*x-2*y=-15
- Equação:
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Equação sin(x)=cos(x)
-
Equação x^3=3
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Equação cos(x)=(-1/2)
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Equação sin(x-1)=0
- Integral d{x}:
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-1
- Derivative of:
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-1
- Sum of series:
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-1
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Identical expressions
- - three *x- ten *y=- one
- minus 3 multiply by x minus 10 multiply by y equally minus 1
- minus three multiply by x minus ten multiply by y equally minus one
- -3x-10y=-1
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Similar expressions
- -3*x-10*y=+1
- -3*x+10*y=-1
- 3*x-10*y=-1
Express x in terms of y where -3*x-10*y=-1
O professor ficará muito surpreso ao ver a sua resposta correta 😉
A solução
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 3 x = 10 y - 1$$
Divide both parts of the equation by -3
We get the answer: x = 1/3 - 10*y/3
-3*x-10*y = -1
Looking for similar summands in the left part:
-10*y - 3*x = -1
Move the summands with the other variables
from left part to right part, we given:
$$- 3 x = 10 y - 1$$
Divide both parts of the equation by -3
x = -1 + 10*y / (-3)
We get the answer: x = 1/3 - 10*y/3
Rapid solution
[src]
1 10*re(y) 10*I*im(y)
x1 = - - -------- - ----------
3 3 3
$$x_{1} = - \frac{10 \operatorname{re}{\left(y\right)}}{3} - \frac{10 i \operatorname{im}{\left(y\right)}}{3} + \frac{1}{3}$$
x1 = -10*re(y)/3 - 10*i*im(y)/3 + 1/3