Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- -7*x-20*y=-5
- 5*x-6*y=3
- -20*x+17*y=-16
- -8*x-2*y=-15
- Equation:
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Equation sin(x)=cos(x)
-
Equation x^3=3
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Equation cos(x)=(-1/2)
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Equation sin(x-1)=0
- Limit of the function:
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-5
- -5
- Derivative of:
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-5
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Identical expressions
- - sixteen *x- nine *y=- five
- minus 16 multiply by x minus 9 multiply by y equally minus 5
- minus sixteen multiply by x minus nine multiply by y equally minus five
- -16x-9y=-5
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Similar expressions
- -16*x-9*y=+5
- -16*x+9*y=-5
- 16*x-9*y=-5
Express x in terms of y where -16*x-9*y=-5
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 16 x = 9 y - 5$$
Divide both parts of the equation by -16
We get the answer: x = 5/16 - 9*y/16
-16*x-9*y = -5
Looking for similar summands in the left part:
-16*x - 9*y = -5
Move the summands with the other variables
from left part to right part, we given:
$$- 16 x = 9 y - 5$$
Divide both parts of the equation by -16
x = -5 + 9*y / (-16)
We get the answer: x = 5/16 - 9*y/16
Rapid solution
[src]
5 9*re(y) 9*I*im(y)
x1 = -- - ------- - ---------
16 16 16
$$x_{1} = - \frac{9 \operatorname{re}{\left(y\right)}}{16} - \frac{9 i \operatorname{im}{\left(y\right)}}{16} + \frac{5}{16}$$
x1 = -9*re(y)/16 - 9*i*im(y)/16 + 5/16