Mister Exam
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How to use it?
- Express {x} in terms of y where:
- -6*x-17*y=14
- 4*x-18*y=-14
- -14*x-1*y=3
- 1*x-6*y=-19
- Equation:
-
Equation (x-5)/2=2*(3x/7-1/2)/3
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Equation cos(x/2)=(1/2)
-
Equation x^4-4*x^3-2*x^2+12*x+9=0
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Equation sin(x)=-1
- Derivative of:
- 14
- Integral of d{x}:
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14
- Sum of series:
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14
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Identical expressions
- - six *x- seventeen *y= fourteen
- minus 6 multiply by x minus 17 multiply by y equally 14
- minus six multiply by x minus seventeen multiply by y equally fourteen
- -6x-17y=14
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Similar expressions
- -6*x+17*y=14
- 6*x-17*y=14
Express x in terms of y where -6*x-17*y=14
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 6 x = 17 y + 14$$
Divide both parts of the equation by -6
We get the answer: x = -7/3 - 17*y/6
-6*x-17*y = 14
Looking for similar summands in the left part:
-17*y - 6*x = 14
Move the summands with the other variables
from left part to right part, we given:
$$- 6 x = 17 y + 14$$
Divide both parts of the equation by -6
x = 14 + 17*y / (-6)
We get the answer: x = -7/3 - 17*y/6
Rapid solution
[src]
7 17*re(y) 17*I*im(y)
x1 = - - - -------- - ----------
3 6 6
$$x_{1} = - \frac{17 \operatorname{re}{\left(y\right)}}{6} - \frac{17 i \operatorname{im}{\left(y\right)}}{6} - \frac{7}{3}$$
x1 = -17*re(y)/6 - 17*i*im(y)/6 - 7/3