Mister Exam
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How to use it?
- Express {x} in terms of y where:
- 6*x+10*y=-2
- -18*x+12*y=17
- -4*x+3*y=9
- -2*x-19*y=-11
- Equation:
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Equation sin(x)=cos(x)
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Equation x^3=3
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Equation cos(x)=(-1/2)
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Equation (x+7)*(x-1)=0
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Identical expressions
- - nineteen *x- one *y= four
- minus 19 multiply by x minus 1 multiply by y equally 4
- minus nineteen multiply by x minus one multiply by y equally four
- -19x-1y=4
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Similar expressions
- -19*x+1*y=4
- 19*x-1*y=4
Express x in terms of y where -19*x-1*y=4
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 19 x = y + 4$$
Divide both parts of the equation by -19
We get the answer: x = -4/19 - y/19
-19*x-1*y = 4
Looking for similar summands in the left part:
-y - 19*x = 4
Move the summands with the other variables
from left part to right part, we given:
$$- 19 x = y + 4$$
Divide both parts of the equation by -19
x = 4 + y / (-19)
We get the answer: x = -4/19 - y/19
Rapid solution
[src]
4 re(y) I*im(y)
x1 = - -- - ----- - -------
19 19 19
$$x_{1} = - \frac{\operatorname{re}{\left(y\right)}}{19} - \frac{i \operatorname{im}{\left(y\right)}}{19} - \frac{4}{19}$$
x1 = -re(y)/19 - i*im(y)/19 - 4/19