Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- -7*x-20*y=-5
- 5*x-6*y=3
- -20*x+17*y=-16
- -8*x-2*y=-15
- Equation:
-
Equation sin(x)=cos(x)
-
Equation x^3=3
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Equation cos(x)=(-1/2)
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Equation sin(x-1)=0
- Integral of d{x}:
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-7
- Limit of the function:
- -7
- Derivative of:
- -7
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Identical expressions
- - nine *x+ sixteen *y=- seven
- minus 9 multiply by x plus 16 multiply by y equally minus 7
- minus nine multiply by x plus sixteen multiply by y equally minus seven
- -9x+16y=-7
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Similar expressions
- -9*x-16*y=-7
- -9*x+16*y=+7
- 9*x+16*y=-7
Express x in terms of y where -9*x+16*y=-7
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 9 x = - 16 y - 7$$
Divide both parts of the equation by -9
We get the answer: x = 7/9 + 16*y/9
-9*x+16*y = -7
Looking for similar summands in the left part:
-9*x + 16*y = -7
Move the summands with the other variables
from left part to right part, we given:
$$- 9 x = - 16 y - 7$$
Divide both parts of the equation by -9
x = -7 - 16*y / (-9)
We get the answer: x = 7/9 + 16*y/9
Rapid solution
[src]
7 16*re(y) 16*I*im(y)
x1 = - + -------- + ----------
9 9 9
$$x_{1} = \frac{16 \operatorname{re}{\left(y\right)}}{9} + \frac{16 i \operatorname{im}{\left(y\right)}}{9} + \frac{7}{9}$$
x1 = 16*re(y)/9 + 16*i*im(y)/9 + 7/9